VI SOLVES MAZE (and lies about it)

[Dean "Flash" Fashbaugh]

In article <44914 at mips.mips.COM> jc at mips.COM (J.C. Webber III) writes:
>
>Wouldn't compile for me either.  Complained about srand and drand I think.

Here's what I get:
=================================================================
% cat maze.c
char*M,A,Z,E=40,J[40],T[40];main(C){for(*J=A=scanf(M="%d",&C);
--            E;             J[              E]             =T
[E   ]=  E)   printf("._");  for(;(A-=Z=!Z)  ||  (printf("\n|"
)    ,   A    =              39              ,C             --
)    ;   Z    ||    printf   (M   )) M[Z]=Z[A-(E =A[J-Z]) &&!C
&    A   ==             T[                                  A]
|6<<27<rand()||!C&!Z?J[T[E]=T[A]]=E,J[T[A]=A-Z]=A,"_.":" |"];}

% cc maze.c -o maze
"maze.c", line 5: non-integral subscript in array reference
"maze.c", line 7: non-integral subscript in array reference
=================================================================

I am only a novice C programmer and can't figure a way around this. (I tried
a multitude of "things", after finding the "A-Z" in the subscript to be the
culprit, but nothing worked....)

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