Pointer Trouble Right Here in Unix City

[Doug Gwyn <gwyn>]

> 			*(*argv + 2) ? *argv += 2 : argv++;

cond ? expr1 : expr2

If expr1 and expr2 are both pointers, they must have the same type.
(Section C.3.15 of ANSI X3J11/85-008)

You could write
	*(*argv + 2) ? (*argv += 2) : *(argv++);
but this is hardly the most readable code in any case.

P.S.  Consider using the public-domain getopt() that I posted
a while back.  (You can easily disable the checks that preclude
-xargument style options in favor of -x argument.  I think those
restrictions in the spec are pretty silly anyway.)