Floating point puzzle

[Alan J Rosenthal]

In article <259 at quintus.UUCP> ok at quintus.UUCP (Richard A. O'Keefe) writes:
>TRAP:  floating-point constants such as 1.0 are DOUBLE precision, so if the
>compiler sees float x; ... x+1.0, it will do the addition in double
>precision.  In such a case, I do	float one = 1.0; ... x+one...

AACKK.. Pascal programmer detected.  Use a cast.  "x + (float)1.0" is the
same as "x + one" in your example.  At least, it should be.

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