Re^2: Turbo C 2.0 vs MSC 5.1
Larry Jones
scjones at sdrc.UUCP
Sun Aug 13 03:31:35 AEST 1989
In article <1631 at crdgw1.crd.ge.com>, davidsen at sungod.crd.ge.com (ody) writes:
> In article <1989Aug9.094742.20000 at gdt.bath.ac.uk> exspes at gdr.bath.ac.uk (P E Smee) writes:
>
> | A bad move, I'd have said. It is not difficult to think of cases where
> | 'a/b/c/d/e' would give a sensible answer, while 'a/(b*c*d*e)' will
> | overflow computing the denominator '(b*c*d*e)' and so give nonsense.
>
> Could you give us an example? Looking at the conditions it sure looks
> as though even by avoiding the overflow you would be doing the
> equivalent operations and would get an underflow on one of the divides.
For simplicity, lets consider just a/b/c vs. a/(b*c). If a and b
are equal and very large (like DBL_MAX, for example) and c is
some small integral value (like 2.0), then a/b/c is a quite
reasonable, representable value (0.5), but a/(b*c) causes an
overflow (since 2.0 * DBL_MAX is not representable).
----
Larry Jones UUCP: uunet!sdrc!scjones
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"I have plenty of good sense. I just choose to ignore it."
-Calvin
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