passing *char parameters by reference

[Karl Heuer]

In article <750 at greens.UUCP> matthew at sunpix.UUCP ( Sun Visualization Products) writes:
>(...I've taken the liberty of converting them to type 'void', since pointer
>type is only important when doing mathimatical operations on the pointers
>themselves.)

Uh, that's not quite true.

>	void swap(x,y) void **x, **y; {
>	    register void *temp;
>	    temp = *x;  *x = *y;  *y = temp;
>	}

This is a function that can be used to swap two |void *| objects.  Because of
a grandfather clause, it can also be used to swap two |char *| objects.  It is
*not* necessarily true that it can swap |int *|s, though; on some machines
|char *| and |int *| have different representations, and there's no guarantee
that they even have the same length.

Karl W. Z. Heuer (ima!haddock!karl or karl at haddock.isc.com), The Walking Lint