Is ``char c; strcpy(&c,"");'' ANSI C?

[Doug Gwyn]

In article <30 at looney.twinsun.com> eggert at twinsun.com (Paul Eggert) writes:
>	...  char c; strcpy(&c, ""); ...		(1)
>is not ANSI C, because strcpy calculates (&c) + 1, violating K&R A7.6, p.205,

It's not a problem.  The (proposed) C standard in effect guarantees that
every object can be considered as an array of one thing, and that it is
always legal to generate a pointer to the thing one past the last element
of any array, although it is not legal to dereference such a pointer.