precedence of && (was: precedence of ?:)

[Tom Karzes]

Neither of the following are legal because conditional expressions (?:) are
not regarded as lvalues:

    (a ? b : c) = d
    (a ? *b : *c) = d

However, the following is legal since indirection expressions (*) are legal
lvalues:

    *(a ? b : c) = d

I personally don't see why ?: expressions can't be lvalues, provided the
second and third operands have the same type.  For example, the following
would be legal, with result type int:

    int a, b, c[10], d, i;
    ...
    (a ? b : c[i]) = d;

But the following would be illegal:

    int a, b, d;
    double c;
    ...
    (a ? b : c) = d;

Oh well...