typedef-ing an array

[Roger Meunier]

In article <78633 at srcsip.UUCP> pclark at SRC.Honeywell.COM (Peter Clark) writes:

 > What I meant was, why doesn't this work:
 >
 >-----------------------------------------
 >
 >#include <stdio.h>
 >
 >typedef char foo[29];
 >
 >/* a string with 28 chars, add one for the NULL byte */
 >foo bar = "Hello World, this is my test";
 >
 >void
 >  main()
 >{
 >  bar = "Silly old me";
 >  printf("%s\n",bar);
 >}
 >--------------------------------------------------

The variable "bar" is declared as a static string.  That is not the
same as declaring "char* bar" which is necessary for the assignment
statement.  I don't believe standard C even hints that strings are
copied by assignment statements.  A *pointer* to the literal string
is assigned to lhs, and in your example bar's type won't accept a
pointer.  Try 'char* bar = "Hello World, this is my test";' instead.
Clear as mud?
--
Roger Meunier @ Zuken, Inc.  Yokohama, Japan	(roger at zuken.co.jp)