Compound Assignments (was Re: Another <sigh> error!)

[D'Arcy J.M. Cain]

In article <1991Apr6.195901.25255 at dvorak.amd.com> Tim Olson writes:
>| 	x *= y;
>| 	x = x * y;
>In the second example, "x" is not evaluated twice -- it is evaluated
>only once, just as in the first example.  The standard says just this
>in 3.3.16.2 (Compound assignment):
>	A compound assignment of the form E1 op= E2 differs from the
>	simple assignment expression E1 = E1 op (E2) only in that the
>	lvalue E1 is evaluated only once.

Huh?  Am I missing something or does that say that the two expressions
*ARE* evaluated differently?  What it says is that the number of times
x is evaluated is the *only* difference but it is a difference.

-- 
D'Arcy J.M. Cain (darcy at druid)     |
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