sizeof and multi-dimensional arrays

[Rory Jacobs]

In article <4596 at sactoh0.SAC.CA.US> jak at sactoh0.SAC.CA.US (Jay A. Konigsberg) writes:

>sizeof(*x)   DOES NOT make sense. The size of a pointer on this machine
>	     is 4 bytes. (Note: adding "char *y; sizeof(y) does return 4).
>

But it does make sense.

In a sense the array name is a pointer to the array.  To access
the i-th element in an array you could write
   foo[i]

or

   *(foo + i)

Both statements return the i-th element.  

Now back to the orignal problem, since the above is true (convient
as pointer arithmatic is faster than array indexing) *x is equivalent
to *(x+0) which is x[0], and thus they have the same size.

Hope this helps,
   Rory

Rory Jacobs                                   Who me?!?
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