Question about assertion macro

[Don McCrady]

>>From: greg at suntan.viewlogic.com (Gregory Larkin)
>>I would like to construct an assertion macro so that I
>>can print the exact condition that failed as a string.
>>   ASSERT(foo != NULL, "Unexpected NULL pointer");
>>Greg Larkin (ASIC Engineer)

> #define ASSERT_ARG(relation, msg, action) \
> if ( !(relation) ) { \
>   printf("ASSERTION FAILED: File %s Line %d %s %s\n",\
>   __FILE__, __LINE__, "relation", msg);\
>   action; \
> } /* if assertion failed */
>
> should work in standard C; I'm not sure about ANSI C, though.
> From: msh30 at ruts.ccc.amdahl.com (Mark Hahn)

No, this won't work in ANSI C... If you use an ANSI C preprocessor,
you can do this easily with the "stringize" operator, #... Try this:

  #define ASSERT_ARG(relation, msg, action) \
    if ( !(relation) ) { \
      printf("ASSERTION FAILED: " #relation "File %s Line %d %s\n",\
             __FILE__, __LINE__, msg); \
      action(); \
    }

Better yet, if you have an ANSI compiler, you should have a header
file called <assert.h>, which will do exactly what you want; that
is, print the failing assertion, the file and line number, and call
the abort() function to terminate the program.

Enjoy.

             ++Don;