passing address of floating-point parameter
chris ross
cjross at bbn.com
Wed Jun 12 12:00:42 AEST 1991
Here's something to feed to your compiler.
Define a routine which takes a (float) parameter and passes the address to a
routine which expects a (float*). What value do you get when following the
pointer in the second routine? Under Vax Ultrix and Masscomp RTU, I get
what I passed the first routine. Under SunOS and MIPS RISC/OS, I get
something different.
Here's the code. It should print
1 1
1 1
main ()
{
foo(1.0, 1.0);
}
foo (x, y)
float x, y;
{
float local_x = x;
show(&local_x, &y);
printf("%g %g\n", x, y);
}
show (xp, yp)
float *xp, *yp;
{
printf("%g %g\n", *xp, *yp);
}
Apparently, the Sun and MIPS compilers do not hide the fact that the
parameter in the first routine is actually on the stack as a (double).
Should they, or, as with va_arg, must the programmer explicitly take the
type promotion into account? Does ANSI specify the proper behavior?
---------- chris ross ---------- <cjross at bbn.com> ----------
lisp in action is like a finely choreographed ballet.
ada in action is like a waltz of drugged elephants.
c in action is like a sword dance on a freshly waxed floor.
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