the logical xor operator!

[Karl Heuer]

In article <3254 at rpp386.UUCP> jfh at rpp386.UUCP (The Beach Bum) writes:
>in particular, i believe (a == 0)^(b == 0) most likely can't be as well
>optimized as (a == 0)!=(b == 0).

Nonsense.  "!=" and "^" produce the same result when both operands are
normalized booleans; therefore a compiler which detects this situation is free
to generate its favorite logical-xor construct for both.  In practice, few if
any compilers bother to do this.

Karl W. Z. Heuer (ima!haddock!karl or karl at haddock.isc.com), The Walking Lint