More Re: Function Argument Evaluation argument

[Roy Johnson]

I understand that the comma operator is a sequence point.
If we use the comma operator as a sequence point between evaluations:

   int v=1;
   printf("%d %d\n", (1, v), (1,v++));

This can print
	1 1
or
	2 1
if I understand it right, which I very well may not.

Similarly,

   char *x="foo", *y="bar", *p;
   p=x;
   printf("%s %s\n", (1, (p=y)), (1, p));

can print

	foo bar
or

	bar bar

Do I win?  8^)
--
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Roy Johnson, Shell Development Company