shell / awk question

[Eric van Wessel]

quota | awk 'BEGIN { FS=" " } { quot=$2 }
	     END { printf "%d\n",quot } '
				  ^^
				  How to make quot known here ?
							  |
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du -s $HOME |						  |
awk 'BEGIN { FS=" " } { printf "\nDiskspace\n";		  |
			printf "---------\n";		  |
			used=($1)/2;			  |
			free=quot-used }  <----------------
     END   { printf "Used : %d kb. (%d%%)\n",used,used/(quot/100) ;
	     if (free>=0)
	       printf "Free : %d kb.\n\n",free
	     else printf "Too much : %d kb.\n\n",-free } '




Does anyone know?
Please e-mail ( emwessel at praxis.cs.ruu.nl )

Thanks, Eric