Void function pointers

[Suzanne Arroyo]

In article <2887 at casbah.acns.nwu.edu>  hpa at casbah.acns.nwu.edu (Peter Anvin) writes:
>	Turbo C++ always terminates with a hard "Type mismatch" error.  Is this
>	correct behavior.....?

Yes!  Function foo was defined as:

	void foo ( int p1, double p2, void ( *zoom)(int x, double y))

ie, taking three parameters: an int, a double, and a *pointer to a function returning void**

foo was called later with a pointer to a function returning *int* - causing the obvious
type mismatch

>	is there a way to declare a pointer to a function returning *anything or void* but
>	still specify its parameters?

A function must be declared with a single type - if you want it to be a catch-all type, then
void is your choice - the problem there is passing the right type function pointer

this works, but is messy:
	foo ( 7, 3.131592653938789, (void(*)(int, double) )bar);

hope this helps

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 Suzanne Arroyo					Wusses Are Fun People!!!!
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