argc[argv]

[Alan S. Driscoll]

	From: Laws at SRI-AI.ARPA
	Newsgroups: net.unix
	Subject: argc[argv]
	
	From:  Ken Laws <Laws at SRI-AI.ARPA>
	
	Beginners may have trouble with the statement that a[b] is entirely
	equivalent to *(a+b).  This is only true for character arrays.  For
	other types of arrays the translation is *(a+b*sizeof(*a)).
	
						-- Ken Laws


No, that's incorrect -- "a[b]" is equivalent to "*(a+b)".  If "a" is a
pointer, and "b" an integer, then the multiplication you described will
take place, but not for the reason you gave.  The multiplication is a
result of the way the "+" operator is defined in C.  In "*(a+b)", the
very same multiplication will take place.


	Alan S. Driscoll
	AT&T Bell Laboratories