Csh substitution

[liberte at uiucdcsp.UUCP]

This csh trick has been puzzling me too long:

Inside a command substitution, I want to do a variable substitution but
not a filename expansion on the variable's value.  I cant seem to get one
without the other.  For example:

	set x = "ls .*"
	set z = `echo $x`
	echo "$z"

outputs:
	ls . .. .cshrc .login

which is reasonable, but what I want is:
	ls .*

You would think that using "$x" or $x:q instead of $x would do it:
	set z = `echo "$x"`

Surprise.  Same thing results.

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If we try:
	
	set x = "ls .*"
	set y = '"$x"'
	set z = `echo $y`
	echo $z		# notice no '"'s

we get:
	"$x"

since the '"'s are quoted too.  

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So let's try:

	set z = `eval echo $y`
	echo "$z"

back to:
	ls . .. .cshrc .login

----------------------------------
Same thing with:
	set z = `eval echo " $x:q "`
and
	set z = `echo " $x:q "`
and
	set y = "echo $x:q"
	set z = `$y`

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I am out of creative ideas...

mail and I'll post,
Daniel LaLiberte
University of Illinois, Urbana-Champaign
	usenet:	 ihnp4!uiucdcs!liberte
	arpanet: liberte at uiucdcs.Uiuc.ARPA